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hi ,
in this question poin to consider is that , block 2m is not involed in any type of motion, it wil remain unmoved . so for no slipping block m should also be at rest
consider block m,
net force on it should be zero,
T - μmg = 0
T = F ,so
μ = F /mg , it will be its min. value (a)
Hi,
Sorry for that,
actually I didn't consider the other block
if see in the fig ,
the max accelaration of the combined system of both block = F/3m
now we hav to find the u for this condition
total horz. force on the block 2 => umg - F =m*F/3m =F/3
=>umg = 4F/3
=>u(min.)=4F/3mg
minimum u value ensure no slipping at all, maens that the both block will move together for that given value of FORCE
I really appreciate ur move bcz of which i cud correct my mistake
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