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Grade 12Mechanics

4429-936_5946_untitled2.jpg the min. value of µ b/w the two blocks for no slipping is a) F/mg b) F/3mg c) 2F/3mg d) 4f/3mg

Profile image of Saurabh tiwari
16 Years agoGrade 12
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4 Answers

Profile image of Pratham  Ashish
16 Years ago

hi ,

in this question poin to consider is that , block 2m is not involed in any type of motion, it wil remain unmoved . so for no slipping  block m should also be at rest

 consider block m,

  net force on it should be zero,

 T - μmg = 0

T = F ,so

μ =  F /mg , it will be its min. value (a)

Profile image of Saurabh tiwari
16 Years ago
no! ans is not correct!
Profile image of Pratham  Ashish
16 Years ago

Hi,

 

Sorry for that,

 

actually I didn't consider the other block 

 

if see in the fig ,

 

4490-992_4788_fig.jpg

the max accelaration of the combined system of both block =  F/3m

 

now we hav to find the u for this condition

total horz. force on the block 2 =>   umg - F =m*F/3m =F/3

 

                                          =>umg = 4F/3

 

                                         =>u(min.)=4F/3mg

 

minimum u value ensure no slipping at all,  maens that the both block will move together for that given  value of FORCE

 

I really appreciate ur move bcz of  which i cud correct my mistake

 

ENJOY the  solution

Profile image of yudhvir maan
15 Years ago

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