# the min. value of µ b/w the two blocks for no slipping is a) F/mg b) F/3mg c) 2F/3mg d) 4f/3mg

Pratham Ashish
17 Points
12 years ago

hi ,

in this question poin to consider is that , block 2m is not involed in any type of motion, it wil remain unmoved . so for no slipping  block m should also be at rest

consider block m,

net force on it should be zero,

T - μmg = 0

T = F ,so

μ =  F /mg , it will be its min. value (a)

Saurabh tiwari
18 Points
12 years ago
no! ans is not correct!
Pratham Ashish
17 Points
12 years ago

Hi,

Sorry for that,

actually I didn't consider the other block

if see in the fig ,

the max accelaration of the combined system of both block =  F/3m

now we hav to find the u for this condition

total horz. force on the block 2 =>   umg - F =m*F/3m =F/3

=>umg = 4F/3

=>u(min.)=4F/3mg

minimum u value ensure no slipping at all,  maens that the both block will move together for that given  value of FORCE

I really appreciate ur move bcz of  which i cud correct my mistake

ENJOY the  solution

yudhvir maan
18 Points
11 years ago