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# Two particles a & b,each of mass m are kept stationary by applying a horizontal force F=mg on particle B as shown in fig. then a) tanß = 2tana b) 2T1=5T2 c) rt2T1=rt5T2 d) noe of the above

Pratham Ashish
17 Points
12 years ago

hi,

at point B,

T2*cosβ = mg .....(in vertical dirxn).............[1]

T2*sinβ = mg........(in horizontal dirxn)........[2]

dividing these 2 eqns, we get

tanβ = 1 ,.i.e β = ∏/4......

now at pont A,

T1*cosα = T2*cosβ + mg........(in vertical dirxn).................[3]

=> T1*cosα = 2T2*cosβ........(using [1])

in horizontal dirxn

T1*sinα = T2*sinβ ........................[4]

dividing 4 by 3 ,we get

tanα = 0.5*tanβ

=>  2tanα = tanβ

so correct option is (a)........