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B and C accelerate downward at (2*3 -3)g/9 =g/3, let the tension in string connecting B and C be T.
3*g-T=3*(g/3)
solve for T
That gives the tension in the string connecting Block B and C.
Regards,
Ashwin (IIT Madras)
first we take a+b+c as a system
(6g-3g)/9=a
a=g/3
now
force on C
3g-T=3*g/3
T=2g
accln=g/3 =>3g-T=3g/3 T=2g
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