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        I have a problem in solving the following question, Can some one provide me the detailed solution of it,
The moment of inertia of a uniform semicircular disc of mass M and radius r about a line perpendicular to the plane of the disc through the centre is ...?
11 years ago

dev bhatnagar
8 Points
							This a simple conceptual question I think following can help you
Mass of semicircular disc = M
Suppose there is a circular disc of mass 2M, then
Moment of intertia of circular disc = 1/2(2M)R2
Moment of intertia of circular disc = 1/2(2M)R2 = MR2
=> So, Moment of intertia of semi-circular disc = (1/2)MR2

11 years ago
sowmya thandra
8 Points
							can i get to know the detail information abt calculating moment of inertia

11 years ago
Tripti Arora
11 Points
							The above answer is right but from wrong method because moment of inertia is same for any arc or any part of disc it is not that if disc is half then mass is also half and Moi also half

2 years ago
parth
13 Points
							As it is uniform the mass didtribution is same all over the disc so half of the disc results in ½ of mass 	m=density(d)*vol	M1=d*t*$\displaystyle \pi$R2	M2=d*t*$\displaystyle \pi$(r/2)2

one year ago
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Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions