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Mechanics

two particles are throewn from a certain height0along horizontal direction mutually opposite to each other with velocities V1 AND V2.

find the distance between the particles when velocity vector becomess mutually perpendicular.

Profile image of shiwani sharma
15 Years agoGrade
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1 Answer

Profile image of Chetan Mandayam Nayakar
14 Years ago

let 't' be time. velocity vectors are v1(t) =V1ti+gtj,and v2(t)= -V2ti+gtj

when velocity vector is mutually perpendicular at t=tp, v1(tp)·v2(tp)=0

let h be initial horizontal distance

at tp distance=ltp(V1+V2)-hl