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two particles are throewn from a certain height0along horizontal direction mutually opposite to each other with velocities V1 AND V2.
find the distance between the particles when velocity vector becomess mutually perpendicular.
let 't' be time. velocity vectors are v1(t) =V1ti+gtj,and v2(t)= -V2ti+gtj
when velocity vector is mutually perpendicular at t=tp, v1(tp)·v2(tp)=0
let h be initial horizontal distance
at tp distance=ltp(V1+V2)-hl
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