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Pushing force making an angle theta to the horizontal is applied on a block of weight w placed ona a horizontal table. If the angle of friction is alpha , the magnitude of force required to move the body is equal to a) (w cos(alpha))/(cos(theta+alpha)) b) (w sin(theta))/(cos(theta+alpha)) c) (w tan(theta))/(sin(theta+alpha)) d) (w sin(alpha))/(tan(theta+alpha))

Pushing force making an angle theta to the horizontal is applied on a block of weight w placed ona a horizontal table. If the angle of friction is alpha, the magnitude of force required to move the body is equal to


a) (w cos(alpha))/(cos(theta+alpha))


b) (w sin(theta))/(cos(theta+alpha))


c) (w tan(theta))/(sin(theta+alpha)) 


d) (w sin(alpha))/(tan(theta+alpha))

Grade:12th Pass

2 Answers

Saurabh
13 Points
4 years ago
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Ananya
11 Points
3 years ago
N=normalF=force requiredf=frictionN=w+Fsin(theta)tan(alpha)=muf=tan(alpha)[w+fsin(theta)]Fcos(theta)=tan(alpha)[w+Fsin(theta)]F[cos(theta)-tan(theta)sin(theta)]= tan(alpha)wF=[wsin(alpha)]/[cos(theta)*cos(alpha)- sin(theta)*sin(alpha)]F=wsin(alpha)/cos(alpha+theta)

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