#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91 7353221155

CART 0

• 0
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

# Pushing force making an angle theta to the horizontal is applied on a block of weight w placed ona a horizontal table. If the angle of friction is alpha, the magnitude of force required to move the body is equal toa) (w cos(alpha))/(cos(theta+alpha))b) (w sin(theta))/(cos(theta+alpha))c) (w tan(theta))/(sin(theta+alpha)) d) (w sin(alpha))/(tan(theta+alpha))

Saurabh
13 Points
4 years ago
B vb b b b h c g. G h v h j h j hn j h j j j bj nj jn jb jb v. Gv gb. H. Hjk jkn. Hv njgd. Hkb. Hg h g j k l g c d sa e r t yu ui i i ilp hk j g h. Ub ubbub. Jb j hb.
Ananya
11 Points
3 years ago
N=normalF=force requiredf=frictionN=w+Fsin(theta)tan(alpha)=muf=tan(alpha)[w+fsin(theta)]Fcos(theta)=tan(alpha)[w+Fsin(theta)]F[cos(theta)-tan(theta)sin(theta)]= tan(alpha)wF=[wsin(alpha)]/[cos(theta)*cos(alpha)- sin(theta)*sin(alpha)]F=wsin(alpha)/cos(alpha+theta)