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Velocity of a stone projected, 2 seconds before it reaches the maximum height, makes an angle 53 degrees with the horizontal. Find the velocity at the highest point.

Akash Sood , 14 Years ago
Grade 11
anser 1 Answers
ANIKET ROY
Acc to ques, 2 seconds before it reaches the maximum height it makes an angle of 53 deg
=> Initial velocity of y-component will be (Uy)=Usin53
=> Initial velocity of x-component will be (Ux)=Ucos53
Therefore, Vy=Uy-gt
               =>0=Usin53-20
               =>U=25m/s
Now, At highest point the y-component velocity is 0, only x-comp velocity exists which remians constant throughout the projectile motion.
Hence, At highest point the overall velocity of stone will be equal to the x-component velocity
ie, Ucos53=25x3/5=15m/s ANSWER
 
                  
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