# a jet airplane is travelling at a speed of 500km/h.it ejects its products at the speed of 1500km/h relative to the jet plane.what is the speed of the latter with respect to an observer at the ground?

24 Points
10 years ago

Dear Abhishek Choudhary,

Velocity of jet w.r.t. ground Vjg= 500 km/h                                                                …...(Upward)

Velocity of products relative to jet VPJ = 1500 km/h                                                …(downward)

Hence, velocity of  products relative to ground = -1500+500

=  -1000 km/h

Here – ve sing means downward .

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Rishi Sharma
one year ago
Dear Student,

Velocity of jet w.r.t. ground Vjg= 500 km/h …...(Upward)
Velocity of products relative to jet VPJ = 1500 km/h ……(downward)
Hence, velocity of products relative to ground = -1500+500 = -1000 km/h
Here – ve sing means downward .

Thanks and Regards