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a jet airplane is travelling at a speed of 500km/h.it ejects its products at the speed of 1500km/h relative to the jet plane.what is the speed of the latter with respect to an observer at the ground?
Dear Abhishek Choudhary,
Velocity of jet w.r.t. ground Vjg= 500 km/h …...(Upward)
Velocity of products relative to jet VPJ = 1500 km/h …(downward)
Hence, velocity of products relative to ground = -1500+500
= -1000 km/h
Here – ve sing means downward .
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