Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
A particle is oscillating about x=0 along x-axis. The potential energy is given by U=k|x|3 where k is a positive constant. What is the time period of the oscillations of the particle?
Hi, U asked about time period os the osccilation corresponding above Eqn but , hre this in not the case similiar to SHM , here time period depends on Amplitude HOW? if u compare the dimensions of both side then, the dimension of k = [ML-2T-2] T proportional to (mass)x(amplitude)y(k)z RHS = [M]x[L]y [ML-2T-2]z LHS =[T] => x= 1/2 , y = z = -1/2 hence the time period depends over 1/sqrt(k) this was good qn , we welcome all ur qns nd eager to asnweer them. GOOD LUCK FOR UR PREPARATION
Hi,
U asked about time period os the osccilation corresponding above Eqn
but , hre this in not the case similiar to SHM , here time period depends on Amplitude
HOW?
if u compare the dimensions of both side then, the dimension of k = [ML-2T-2]
T proportional to (mass)x(amplitude)y(k)z
RHS = [M]x[L]y [ML-2T-2]z
LHS =[T]
=> x= 1/2 , y = z = -1/2
hence the time period depends over 1/sqrt(k)
this was good qn , we welcome all ur qns nd eager to asnweer them.
GOOD LUCK FOR UR PREPARATION
Find solution of question on doubt solving app Instasolv
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -