A 8000 kg engine pulls a train of 5 wagons ,each of 2000 kg along a horizontal track.If the engine exerts a force of 40000 N and the track offers a friction force of 5000 N,then calculate:

(a)the net accelerating force;

(b)the acceleration of the train ;and

(c)the force of wagon 1 on wagon 2.

a)35000 N

b)35000/(5*2000+8000)='a'

c) a*8000

) The net accelerating force= Force exerted by engine – Force of fricition= 40000 N – 5000 N = 35000 N(b) The acceleration of the trainWe know that, F = mass x accelerationOr, 35000 N = (mass of engine + mass of 5 wagons) X aOr, 35000 N = (8000 kg + 10000 kg) X aOr, 35000N = 18000 kg X a⇒a=35000N18000 kg=1.944ms−2⇒a=35000N18000 kg=1.944ms-2(c) The force of wagon 1 on wagon 2Since, net accelerating force = 35000 NMass of all 5 wagons = 10000 kgWe know that, F = m x aTherefore, 35000N = 10000 kg x a⇒a=35000N10000 kg=3.5ms−2⇒a=35000N10000 kg=3.5ms-2Therefore, acceleration of wagons =3.5m/s2=3.5m/s2Thus, force of wagon 1 on 2 = mass of four wagons x acceleration⇒F=4×2000 kg×3.5ms−2⇒F=4×2000 kg×3.5ms-2⇒F=8000 kg×3.5ms−2⇒F=8000 kg×3.5ms-2⇒F=28000N⇒F=28000NThus, (a) The net accelerating force = 35000N(b) The acceleration of train = 1.944 ms–2(c) The force of wagon 1 on 2 = 28000N