Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

a rod of mass m and length l lies in the axis, with its centre at the origin. what is its moment of inertia about the line x=y?

a rod of mass m and length l lies in the  axis, with its centre at the origin. what is its moment of inertia about the line x=y?

Grade:

1 Answers

vikas askiitian expert
509 Points
9 years ago

dear reshab ,

 

first take elemental part dx anywhere on the rod & let the distance of this part from origin is x ..

 

angle bw rod & axis is @ = 45o (in this case)

 

perpendicular distance bw that part & axis is r = xsin@

 

mass of this element = m/l (dx)

 

dI (inertia of this small part) = (dm) r2

                                        = (m/l) (xsin@)2 dx

 

I = (msin2@/l) x2dx     lim from -l/2 to l/2

 

after integrating & putting limit we get

 

I = ml2 / 24

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free