if gravel if falling on a conveyor belt at the rate of 0.5kg/sec.............how much extra force ( in N) is needed so as tokeep the belt moving at 2m/s.................pls EXPLAIN EACH STEP!!!
Shivam Bhagat , 13 Years ago
Grade 9
1 Answers
Chetan Mandayam Nayakar
Last Activity: 13 Years ago
F=d/dt(mv)=mdv/dt+vdm/dt=0.5*2=1 N
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