A block of mass 250g is kept on a vertical spring of spring constant 100N/m fixed from below. The spring is now compressed to have a length 10cm shorter than its natural length and the system is released from this position . How high does the block rise?
Plz explain me that: We while using the law of conservation of energy
we shud use 1/2kx2 = 1/2k(h-x)2 + mgh, where h is the height travelled by the spring!
But here we are omitting the term 1/2k(h-x)2 to get the answer. plz explain this thing to me!
A block of mass 250g is kept on a vertical spring of spring constant 100N/m fixed from below. The spring is now compressed to have a length 10cm shorter than its natural length and the system is released from this position . How high does the block rise?
Plz explain me that: We while using the law of conservation of energy
we shud use 1/2kx2 = 1/2k(h-x)2 + mgh, where h is the height travelled by the spring!
But here we are omitting the term 1/2k(h-x)2 to get the answer. plz explain this thing to me!
Abhijat Pandey , 13 Years ago
Grade 12
