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Grade 12Mechanics

A block of mass 250g is kept on a vertical spring of spring constant 100N/m fixed from below. The spring is now compressed to have a length 10cm shorter than its natural length and the system is released from this position . How high does the block rise?

Plz explain me that: We while using the law of conservation of energy

we shud use 1/2kx2 = 1/2k(h-x)2 + mgh, where h is the height travelled by the spring!

But here we are omitting the term 1/2k(h-x)2 to get the answer. plz explain this thing to me!

Profile image of Abhijat  Pandey
15 Years agoGrade 12
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1 Answer

Profile image of Chetan Mandayam Nayakar
14 Years ago

The spring will eventually come to rest at its natural length. When this hapens, its energy becomes zero.