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A block of mass 250g is kept on a vertical spring of spring constant 100N/m fixed from below. The spring is now compressed to have a length 10cm shorter than its natural length and the system is released from this position . How high does the block rise?Plz explain me that: We while using the law of conservation of energywe shud use 1/2kx2 = 1/2k(h-x)2 + mgh,where h is the height travelled by the spring!But here we are omitting the term 1/2k(h-x)2 to get the answer. plz explain this thing to me!

Abhijat Pandey , 13 Years ago
Grade 12
anser 1 Answers
Chetan Mandayam Nayakar

Last Activity: 13 Years ago

The spring will eventually come to rest at its natural length. When this hapens, its energy becomes zero.

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