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two particles move parallel to x axis about origin with same amplitude and frequency.at a certain instant they are found at a distance a/3 from origin on opposite sides but their velocities are found to be in same dirction.find the phase difference between two particles
Dear Pankaj,
let origin is thier reference
1st particle is going awy fom origin. so, its phase is [sin inverse (a/3a)] i.e [sin inverse (1/3)]
similarly phase of 2nd particle is [-sin inverse(1/3)]
Hence the phase difference between above 2 paricles is [2sin inverse(1/3)]
Best Of luck
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