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two particles move parallel to x axis about origin with same amplitude and frequency.at a certain instant they are found at a distance a/3 from origin on opposite sides but their velocities are found to be in some dirction.find the phase difference between two particles will be

two particles move parallel to x axis about origin with same amplitude  and frequency.at a certain instant they are found at a distance a/3 from origin on opposite sides but their velocities are found to be in some dirction.find  the phase difference between two particles will be 

Grade:12th Pass

1 Answers

KARAN ACHARYA
52 Points
10 years ago

this can be solved by phasor method

let origin is thier reference

1st particle is going awy fom origin. so, its phase is [sin inverse (a/3a)] i.e [sin inverse (1/3)]

similarly phase of 2nd particle is  [-sin inverse(1/3)]

 

hene the phase difference between above 2 paricles  is [2sin inverse(1/3)]

 

 

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