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two particles move parallel to x axis about origin with same amplitude and frequency.at a certain instant they are found at a distance a/3 from origin on opposite sides but their velocities are found to be in some dirction.find the phase difference between two particles will be

two particles move parallel to x axis about origin with same amplitude  and frequency.at a certain instant they are found at a distance a/3 from origin on opposite sides but their velocities are found to be in some dirction.find  the phase difference between two particles will be 

Grade:12th Pass

1 Answers

KARAN ACHARYA
52 Points
9 years ago

this can be solved by phasor method

let origin is thier reference

1st particle is going awy fom origin. so, its phase is [sin inverse (a/3a)] i.e [sin inverse (1/3)]

similarly phase of 2nd particle is  [-sin inverse(1/3)]

 

hene the phase difference between above 2 paricles  is [2sin inverse(1/3)]

 

 

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