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Grade 12th PassMechanics

The rate of burning of fuel in a rocket is 50g/s and comes out with velocity 4000 m/s.The force exerted by gas on rocket will be

a.200 N

b.250 N

c.2500000 N

d.25000 N

Profile image of Menka Malguri
15 Years agoGrade 12th Pass
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1 Answer

Profile image of KARAN ACHARYA
15 Years ago

FORCE EXERTED = CHANGE IN MOMENTUM / TIME

rate of burning fuel = 50g/s = 50/1000 kg/s

so F= (50 X 4000) / 1000 = 200 

 

Ans a.200N