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A uniform metal disc of radius R is taken and out of it,a disc of diameter R is cut off from the end.the center of mass of the remaining part will be a.R/4 from the center b.R/3 from the center c.R/5 from the center d.R/6 from the center

A uniform metal disc of radius R is taken and out of it,a disc of diameter R is cut off from the end.the center of mass of the remaining part will be


a.R/4 from the center


b.R/3 from the center


c.R/5 from the center


d.R/6 from the center

Grade:12th Pass

2 Answers

KARAN ACHARYA
52 Points
12 years ago

let origin be the centre of metal disc

0 = [M1X1 +M2X2] / [M1 + M2]

mass of disc of diameter R = M/4

0 = [3m/4 X + (M/4)(R/2)] / [3M/4 + M/4]

X=[-R/6]

 

Ans d.R/6

ankit singh
askIITians Faculty 614 Points
3 years ago

 

Let origin be the centre of metal disc
0=M1​+M2​M1​X1​+M2​X2​​
Mass of disc of diameter R = M/4
0=[3M/4+M/4]3M/4X+(M/4)(R/2)​
X=−[6R​]

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