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Two blocks of masses 10 kg and 4 kg are connected by a spring of negligible mass and placed on a frictionless horizontal surface.An impulse gives a velocity of 14m/s to the heavier block in the direction of the lighter block.the velocity of the center of mass isa.5m/sb.20m/sc.30m/sd.10m/s

Menka Malguri , 13 Years ago
Grade 12th Pass
anser 2 Answers
KARAN ACHARYA

Last Activity: 13 Years ago

Vcm = [m1v1 + m2v2] / [m1+m2]

       = [(10x14) + (4x0)] / [10+4]

       = 10

 

Ans d.10m/s

Rishi Sharma

Last Activity: 4 Years ago

Dear Student,
Please find below the solution to your problem.

Given : m1​=10kg m2​=4kg
Velocity of mass m1​, v1​=14m/s
Velocity of mass m2​ v2​=0
Velocity of centre of mass
Vcm = [m1v1 + m2v2] / [m1+m2]
= [(10x14) + (4x0)] / [10+4]
= 10

Thanks and Regards

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