Two blocks of masses 10 kg and 4 kg are connected by a spring of negligible mass and placed on a frictionless horizontal surface.An impulse gives a velocity of 14m/s to the heavier block in the direction of the lighter block.the velocity of the center of mass isa.5m/sb.20m/sc.30m/sd.10m/s
Dear Student, Please find below the solution to your problem.
Given : m1=10kg m2=4kg Velocity of mass m1, v1=14m/s Velocity of mass m2 v2=0 Velocity of centre of mass Vcm = [m1v1 + m2v2] / [m1+m2] = [(10x14) + (4x0)] / [10+4] = 10
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