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Two blocks of masses 10 kg and 4 kg are connected by a spring of negligible mass and placed on a frictionless horizontal surface.An impulse gives a velocity of 14m/s to the heavier block in the direction of the lighter block.the velocity of the center of mass is a.5m/s b.20m/s c.30m/s d.10m/s

Two blocks of masses 10 kg and 4 kg are connected by a spring of negligible mass and placed on a frictionless horizontal surface.An impulse gives a velocity of 14m/s to the heavier block in the direction of the lighter block.the velocity of the center of mass is


a.5m/s


b.20m/s


c.30m/s


d.10m/s

Grade:12th Pass

2 Answers

KARAN ACHARYA
52 Points
9 years ago

Vcm = [m1v1 + m2v2] / [m1+m2]

       = [(10x14) + (4x0)] / [10+4]

       = 10

 

Ans d.10m/s

Rishi Sharma
askIITians Faculty 646 Points
11 months ago
Dear Student,
Please find below the solution to your problem.

Given : m1​=10kg m2​=4kg
Velocity of mass m1​, v1​=14m/s
Velocity of mass m2​ v2​=0
Velocity of centre of mass
Vcm = [m1v1 + m2v2] / [m1+m2]
= [(10x14) + (4x0)] / [10+4]
= 10

Thanks and Regards

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