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A thin uniform wire is bent to form the two equal sides AB and AC of the triangle ABC ,where AB=AC=5cm.The third side BC=6cm, is made from uniform wire oftwice the density of the first but hte thickness of BC is same as that of AB and AC. Find the distance of the centre of mass from A.

A thin uniform wire is bent to form the two equal sides AB and AC of the triangle ABC ,where AB=AC=5cm.The third side BC=6cm, is made from uniform wire oftwice the density of the first  but hte thickness of BC is same as that of AB and AC. Find the distance of the centre of mass from A.

Grade:Upto college level

1 Answers

Ramesh V
70 Points
12 years ago

The three rods form a triangle as shown below:


4102-1553_5850_untitled.JPG

weight is concentraed at centre of each rod

let mass of AB=AC=d.5.A ,its C.O.M are (4.5 , 2) and (1.5 , 2)

let mass of BC=2d.6.A ,its C.O.M are (3 , 0)

COMx = (5*4.5 +5*1.5+3*12)/(5+5+12) = 3

COMy = (5*2 +5*2+0*12)/(5+5+12) = 0.91

distance P(3 , 0.91) and A(3 , 4) is 3.09m

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Regards,
Ramesh
IIT Kgp - 05 batch




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