Askiitians_Expert Yagyadutt
Last Activity: 13 Years ago
Hello ashutosh ..!
Well the only method in this case is ...
Acceleration = - v.dv/dx
So if curve between v and x is given you can calculate it slope ..or you can say dv/dx
You can find out v is terms of x becAUse the graph of v versus x is given ..if it is parabola ..then v^2 = 4ax ..if it is straight line passing through origin ..v = kx ..or any function like these...( I hope you can find it ..)
Simple then ..multiply the function v with the slope along with -ve sign will give you the acceleration in terms of x
Example :-)
If v^2 = 4ax
then ... 2v.dv/dx = 4a
or v.dv/dx = 2a
-v.dv/dx = -2a
Hence acceleration in this case is constant...and equal to ..-2a ...( and the graph between acceleration and x will be a straight line paralled to x-axis)
Hope it is clear
Regards
Yagya
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