Chetan Mandayam Nayakar
Last Activity: 13 Years ago
let perpendicular distance between bottom of box be y and let horizontal distance covered in box frame be x, let time duration of flight be
2usin(alpha)/gcos(theta)=t, horizontal displacement w.r.t. box=x=ucos(alpha)t-((gsin(theta)t^2)/2),let initial speed be v, zero displacement condition implies that spped of box w.r.t. INCLINED PLANE is such that x=vt+((gt^2)sin(theta)/2)