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a particle moves in a ciorcle of radius 21/22 mwith constant speed 1m/s.find:
a)magnitude of av velocity
b)magnitude of av acceleration in 2 secs.
Dear Student
Particle will cover a distance of 2m in 2sec.
circumference of circle= 2*22/7*21/22 = 6m
in 6m angular displacement is 3600. so in 2m it will be 1200
join centre to the initial and final position of the particle. it will be a triangle with 1200 angle at the centre and other two angle equal to 300 each. length of cord will give the displacement.
if rad is R then
displacement= 2Rcos300= 2*21/22*√3 /2 = 21√3/2
avg vel =disp/time= 21√3/4
let at t=0 v1= i (i is unit vector along x axis) and particle is moving clockwise
at t=2 , v2= -sin300 i + -cos300 j= -i/2 - √3 /2 j
v2-v1= -3i/2 - √3 /2 j
avg acc= (-3i/2 - √3 /2 j)/2
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