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Grade: 12

                        

how to solve the ques. of contraint motion which involve block on table which is connected by pulley & another block suspended freely under gravitation connected with the same pulley!

11 years ago

Answers : (1)

pratham ashish
9 Points
							hi,
  In every qn related to constrained relation u can look for the thing which remain constant.


like in this situation La = length of the string from block A to pulley
                       

                        Lb = length of the string from pulley to block B

now u can look that,
            
                   La+Lb=L  {total lengh of the string whicn is costant }

now differentiating the relatn, we get :

                          Va+Vb=0     {vel. of the bloks}

&                         Aa+Ab=0      {accelrn of the bolcks},


now u can further proceed for solving the problem.


all 3 eqn above r known as constrained relations.

						
11 years ago
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