Use Coupon: CART20 and get 20% off on all online Study Material

Total Price: Rs.

There are no items in this cart.
Continue Shopping
Tushar Watts Grade: 12

The coeff of friction b/w the block A of mass m and triangular wedge B of mass M is @. There is no friction b/w the wedge and the plane. If the system (blockA + wedge B) is released so that there is no sliding b/w A and B, show that the max possible inclination theta is equals to tan -1 @.

8 years ago

Answers : (1)

pratham ashish
9 Points

if  there no frctn b/n B & PLANE
      then, accelrn  of (A+B) wud be g sin(theta). along the plne indwnward diectn,

now cosider the A w.r.t B forces on A    1) psuedo f = m* gsin(theta) upward along th pln
                                         2) gravity = mg vertical dwnwrd
                                         3)max. friction force = @*{mg-mg sin^2(theta)}  
                                        mg sin^2(theta) is vertical compnent of psuedo f   
                                       {mg-mg sin^2(theta)} = total dwn force 
                                       horizontal comp of psuedo f = mg*sin(theta)* cos(theta)
 now in limiting case max frctn f = mg cos^2(theta)
=>  @*mg {1- sin^2(theta)}=mg*sin(theta)*cos(theta)
 => @ = tan(theta)                                     
   =>  theta = tan^-1@.                      

8 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete Physics Course - Class 12
  • OFFERED PRICE: Rs. 2,756
  • View Details
  • Complete Physics Course - Class 11
  • OFFERED PRICE: Rs. 2,968
  • View Details

Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
To Win!!! Click Here for details