Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Sir, Here is my question. A block is kept on a smooth inclined plane of angle of projection theta that moves with a constant accelartion so that the block does not slide relative to the inclined plane.If the inclined plane stops,the normal contact force offered by the plane on the block changes by a factor of what?

Sir,


Here is my question.


A block is kept on a smooth inclined plane of angle of projection theta that moves with a constant accelartion so that the block does not slide relative to the inclined plane.If the inclined plane stops,the normal contact force offered by the plane on the block changes by a factor of what?

Grade:12

1 Answers

Tushar Watts
19 Points
11 years ago

First calculate the acc which will stop the motion. Taking @ = theta

For =lbm, , macos@ = mg sin@

Therefore, a = g tan@

Also, N= ma sin@ + mg cos@

On substitution,

N = ma (cos 2 @ + sin 2@ ) / cos@

Since cos 2 @ + sin 2 @ = 1,

N = ma / cos@

When motion is stopped,

N = ma cos@

Therefore, change = ma cos@ / (ma / cos@ ) = cos 2 @

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free