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Sir, Here is my question. A block is kept on a smooth inclined plane of angle of projection theta that moves with a constant accelartion so that the block does not slide relative to the inclined plane.If the inclined plane stops,the normal contact force offered by the plane on the block changes by a factor of what?
First calculate the acc which will stop the motion. Taking @ = theta For =lbm, , macos@ = mg sin@ Therefore, a = g tan@ Also, N= ma sin@ + mg cos@ On substitution, N = ma (cos 2 @ + sin 2@ ) / cos@ Since cos 2 @ + sin 2 @ = 1, N = ma / cos@ When motion is stopped, N = ma cos@ Therefore, change = ma cos@ / (ma / cos@ ) = cos 2 @
First calculate the acc which will stop the motion. Taking @ = theta
For =lbm, , macos@ = mg sin@
Therefore, a = g tan@
Also, N= ma sin@ + mg cos@
On substitution,
N = ma (cos 2 @ + sin 2@ ) / cos@
Since cos 2 @ + sin 2 @ = 1,
N = ma / cos@
When motion is stopped,
N = ma cos@
Therefore, change = ma cos@ / (ma / cos@ ) = cos 2 @
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