Sir,

Here is my question.

A block is kept on a smooth inclined plane of angle of projection theta that moves with a constant accelartion so that the block does not slide relative to the inclined plane.If the inclined plane stops,the normal contact force offered by the plane on the block changes by a factor of what?

Question

Sir,

Here is my question.

A block is kept on a smooth inclined plane of angle of projection theta that moves with a constant accelartion so that the block does not slide relative to the inclined plane.If the inclined plane stops,the normal contact force offered by the plane on the block changes by a factor of what?

Tushar Watts · Answer

First calculate the acc which will stop the motion. Taking @ = theta

For =lbm, , macos@ = mg sin@

Therefore, a = g tan@

Also, N= ma sin@ + mg cos@

On substitution,

N = ma (cos² @ + sin ²@ ) / cos@

Since cos² @ + sin² @ = 1,

N = ma / cos@

When motion is stopped,

N = ma cos@

Therefore, change = ma cos@ / (ma / cos@ ) = cos ² @

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