A TRAIN IS MOVING TOWARDS NORTH AT ONE PLACE IT TURNS TOWARDS NORTH EAST HERE WE OBSERVE THAT THE RADIUS OF CURVATURE OF OUTER RAIL WILL BE GREATER THAN THAT OF INNER RAIL WHY???PLS EXPLAIN

Dear friend,

This is because the wheels are preferably fixed to the axle and are therefore forced to turn at the same peripheral rotational velocity, this system force the wheel positioned radially inwardly during a turn to slip or slide on the rail, since it travels a shorter distance through a turn than the radially outermost wheel.

The maximum speed of a train on curved track is determined by the following formula:

        V_max = [ (E_a +3) /0.0007d ]^1/2  where  E_a is the height in inches that the outside rail is "superelevated" above the inside rail on a curve and d is the degree of curvature in degrees per 100 feet (30 m). V_max is in miles per hour.

The maximum value of cant (the height of the outer rail above the inner rail) for a standard gauge railway is about 6 inches (150 mm).

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Regards,
Naga Ramesh
IIT Kgp - 2005 batch