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the avg velocity of a body moving with uniform acc. after travelling a distance of 3.06 m is 0.34 m/s. If the change in velocity of the body is 0.8 m/s during this time its uniform acc. is A : 0.01B : 0.02C : 0.03D : 0.04

Shobhit Gupta , 16 Years ago

Grade 12

2 Answers

Sandeep Pathak

Last Activity: 11 Years ago

Let the initial velocity by u and final velocity be v. Then,

Average velocity, $<v> = \frac{v+u}{2} = 0.34 m/s$
Change in velocity is $v-u = 0.8m/s$
This gives, $v = 0.74m/s, u = -0.06m/s$
Using $v^2=u^2+2as$ , you can find the answer.

Yokesh K.K.

Last Activity: 7 Years ago

Average velocity = Total displacement/ Total time

Since it is a straight line motion , displacement = distance.

Therefore, we get t = 9 s

Now

V-U = 2aS

Therefore , a = 0.02 m/s ^2

Correct me if I'm wrong

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Mechanics> kinematics...

the avg velocity of a body moving with uniform acc. after travelling a distance of 3.06 m is 0.34 m/s. If the change in velocity of the body is 0.8 m/s during this time its uniform acc. is A : 0.01B : 0.02C : 0.03D : 0.04

Shobhit Gupta , 16 Years ago

Sandeep Pathak

Yokesh K.K.

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