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the avg velocity of a body moving with uniform acc. after travelling a distance of 3.06 m is 0.34 m/s. If the change in velocity of the body is 0.8 m/s during this time its uniform acc. is A : 0.01B : 0.02C : 0.03D : 0.04
Let the initial velocity by u and final velocity be v. Then,Average velocity,Change in velocity isThis gives,Using, you can find the answer.
Average velocity = Total displacement/ Total timeSince it is a straight line motion , displacement = distance. Therefore, we get t = 9 sNowV-U = 2aSTherefore , a = 0.02 m/s ^2Correct me if I'm wrong
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