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PROJECTILE FIRED FROM AN INCLINED PLANE Consider an inclined palne which makes an with the horizontal. Let a projectile be projected with a velocity 'v' making an angle with the horizontal. Let us choose X axis along the inclined plane and Y-axis perpendicular to it. gcos and gsin are the two rectangular components of g. Now, vx= v cos(-) and vy = v sin(-). Let T = time of flight of the projectile The displacement of the projectile perpendicular to the inclined plane is clearly Zero. Using S = ut + (1/2) a t2, for motion along y-axis, we get 0 = v sin(-) T -(1/2) g cos T2 or T = 2 v sin(-)/g cos Range on the inclined plane is R = 2v2 sin(-) cos/g cos2 Rmax= v2/g (1+sin) Hmax= v2sin2(-)/2g cos
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