Ramesh V
Last Activity: 15 Years ago
The car is moving at speed of 54 km/hr i.e., 15 m/sec
that is initial speed after applying brakes is (u) = 15 m/sec
say at point A, he sees the need to put brakes
at point B, he puts brakes and then car starts deceleratin
at point C, car finally comes to rest
from A to B it moves with speed of 15m/sec in 0.2 sec
so distance covered is S1 = v.t = 15*0.2 = 3 mts
from B to C it moves with constant deceleration of -6 m/sec2 and initial speed of 15m/sec
Using relation V2 - u2 = 2*(-a)*S
S2 = V2/2*a = 15*15 /(2*6) =18.75 mts
the distance travelled by car after he sees need to put brakes is S1+S2
= 21.75 mts ( nearly 22 mts)