A particle is projected with speed 'v' at an angle tetha to the horizontal in a space where the gravitation field changes with horizontal displacement g'=g-ax:here, a= 3g.g/4vvsin2tetha. Find range,time of flightand maximum height ?
akhilesh sharma , 13 Years ago
Grade
1 Answers
Babulal Prasad
Last Activity: 13 Years ago
Mr sharma your question is not clear.
a= 3g.g/4vvsin2tetha
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