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Figure shows a 11.7 ft wide ditch with theapproach roads at an angle of 15 degree with the horizontal. with what minimym speed should a motorcike be moving on the road so that it safely crosses the ditch? Assume that the length of the bike is 5ft, and it leaves the road when the front part runs out of the approach road. For figure see H.C VERMA Page 53
assume bike to be a point object and the length of the ditch be 2.5 + 2.5=0.5feet more wide that is 16.7ft wide because its given that it leaves the road when front part runs out the approach road!!! then apply concept of projectile to determine tha minimum speed with angle of projection being 15 degrees and range being 16.7 feets. hope this give the correct answer!!
assume bike to be a point object and the length of the ditch be 2.5 + 2.5=0.5feet more wide that is 16.7ft wide because its given that it leaves the road when front part runs out the approach road!!!
then apply concept of projectile to determine tha minimum speed with angle of projection being 15 degrees and range being 16.7 feets.
hope this give the correct answer!!
Range = 11.7 + 5 = 16.7ftRange = (u^2 sin2x)/g........16.7 = (u^2 1/2)/32....u = (534.4 *2)^1/2.....u = 32ft/sTherefore the bike`s minimum speed should be 32ft/s to safely land
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