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A target is fixed on the top of a pole 13m high. A person standing at a distance 50m from the pole is capable of projecting a stone with a speed of 31.62m/s. If he wants to strike the target in shortest possible time, at what angle should be project the stone.


A target is fixed on the top of a pole 13m high.  A person standing at a distance 50m from the pole is capable of projecting a stone with a speed of 31.62m/s. If he wants to strike the target in shortest possible time, at what angle should be project the stone.

Grade:11

3 Answers

sushant singh
66 Points
10 years ago

hey venkata

this is the simplest of projectile question...

 

u(x)=31.62cosA 
u(y)=31.62sinA 
a(x)=0 
a(y)=-g 
range/2=50m (for shortest distance) 
so, 2*50=u(x)t 
t=100/31.62cosA----------1. 

height =u(y)t+1/2 a(y) t(sq) 
substitute values of u(y),a(y),height=13 and t from eq 1,solve 4 angle A 

sry the values r not so gud tats y i havent calculated it........

Aditya Nijampurkar
16 Points
9 years ago

try the sum by the trajectory equation!

Diptanil Das
33 Points
9 years ago

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