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A target is fixed on the top of a pole 13m high. A person standing at a distance 50m from the pole is capable of projecting a stone with a speed of 31.62m/s. If he wants to strike the target in shortest possible time, at what angle should be project the stone.
hey venkata
this is the simplest of projectile question...
u(x)=31.62cosA u(y)=31.62sinA a(x)=0 a(y)=-g range/2=50m (for shortest distance) so, 2*50=u(x)t t=100/31.62cosA----------1. height =u(y)t+1/2 a(y) t(sq) substitute values of u(y),a(y),height=13 and t from eq 1,solve 4 angle A sry the values r not so gud tats y i havent calculated it........
try the sum by the trajectory equation!
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