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A uniform circular disc of mass ‘m’ and radius ‘a’ can rotate in a vertical plane about a horizontal axis through a point O on its circumference. The disc is held with the diameter OA through O horizontal and then released. If a constant frictional couple of 'mga/2pie' opposes the motion, the angular speed when OA is vertical will be
I=ma2/2 +ma2=(3/2)ma^2 , loss of potential energy=mga, work done by frictional couple=(mga/2pie)(pie/2), therefore
if w is angular speed, Iw^2= mga-mga/4=3mga/4
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