A uniform ring of mass M and radius R is placed
directly above a uniform sphere of mass 8 M and of
same radius R. The centre of the ring is at a distance
of d = 3 R from the centre of the sphere. The
gravitational attraction between the sphere and the
ring is :

Question

ramendra bahadur singh · Answer

F=G*8M2/16R2 OR F=G*M2/2R2

Rajkuimar Yadav · Answer

ans. 24GM 2 /10(10) 1/2 R 2

sourabh singh · Answer

treat sphere is a ppoint mass and it is same as ring and a particle ...hope u rather know it to found it now

Manish · Answer

Gravitational field due to ring at a distanced=3–√R on its axis isE=GMd(R2+d2)3/2=3–√GM8R2Force on the sphere = mass of sphere × E=8ME=3–√GM2R2

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A uniform ring of mass M and radius R is placed directly above a uniform sphere of mass 8 M and of same radius R. The centre of the ring is at a distance of d = 3 R from the centre of the sphere. The gravitational attraction between the sphere and the ring is :

A uniform ring of mass M and radius R is placed
directly above a uniform sphere of mass 8 M and of
same radius R. The centre of the ring is at a distance
of d = 3 R from the centre of the sphere. The
gravitational attraction between the sphere and the
ring is :

4 Answers

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A uniform ring of mass M and radius R is placed directly above a uniform sphere of mass 8 M and of same radius R. The centre of the ring is at a distance of d = 3 R from the centre of the sphere. The gravitational attraction between the sphere and the ring is :

A uniform ring of mass M and radius R is placeddirectly above a uniform sphere of mass 8 M and ofsame radius R. The centre of the ring is at a distanceof d = 3 R from the centre of the sphere. Thegravitational attraction between the sphere and thering is :

4 Answers

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A uniform ring of mass M and radius R is placed
directly above a uniform sphere of mass 8 M and of
same radius R. The centre of the ring is at a distance
of d = 3 R from the centre of the sphere. The
gravitational attraction between the sphere and the
ring is :