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```
A solid sphere rolls on a rough horizontal surface with a linear speed 7 m/s collides elastically with a fixed smooth vertical wall. Then the speed of the sphere when it has started pure rolling in the backward direction in m/s is.

```
9 years ago

509 Points
```							when it collides with wall then its linear momentam get reversed but there is no change in angular speed ...
speed of center of mass is reversed ...
just after collision ,
angular momentam = mvr - Iw = -mur + 2mur/5 = -3mur/5
after a long time , total angular momentam = mvr + Iw
=mvr + 2mvr/5 = 7mvr/5
since angular mometam is conserved so
7mvr/5 = 3mur/5
v = 3u/7
u = 7 so
v = 3m/s
approve if u like my ans
```
9 years ago
Jaideep Singh Puri
18 Points
```							I am not able to understand the direction of linear momentum in this question.
```
8 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions