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A solid sphere rolls on a rough horizontal surfacewith a linear speed 7 m/s collides elastically with afixed smooth vertical wall. Then the speed of thesphere when it has started pure rolling in thebackward direction in m/s is.
when it collides with wall then its linear momentam get reversed but there is no change in angular speed ...
speed of center of mass is reversed ...
just after collision ,
angular momentam = mvr - Iw = -mur + 2mur/5 = -3mur/5
after a long time , total angular momentam = mvr + Iw
=mvr + 2mvr/5 = 7mvr/5
since angular mometam is conserved so
7mvr/5 = 3mur/5
v = 3u/7
u = 7 so
v = 3m/s
approve if u like my ans
I am not able to understand the direction of linear momentum in this question.
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