Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
For angular simple harmonic motion or physical pendulum torque is calculated about which point or line.( in reference to hc verma part 1 chapter 12 question 26)
in this kind of problems consider oscillation of centre of mass only that will make ur problem easier to solve let the pendulum be at some Φ angle with vertical axis, draw f.b.d ur self, balance the driving force with mg,i.e; F=mg sinΦ so a= F/m=g sinΦ if Φis very small then sinΦ ≈ Φ, a = gΦ =g(x/l) » a proportional to x then use time period formulae, t=2∏ √x/a .
in this kind of problems consider oscillation of centre of mass only that will make ur problem easier to solve
let the pendulum be at some Φ angle with vertical axis, draw f.b.d ur self,
balance the driving force with mg,i.e; F=mg sinΦ
so a= F/m=g sinΦ if Φis very small then sinΦ ≈ Φ,
a = gΦ =g(x/l) » a proportional to x
then use time period formulae, t=2∏ √x/a .
In a physical pendulum the pendulum is hinged about a point and it rotates about that point.........however in this case this point cant be CM ...so the torque has to be take about a point where it does not pass through the line of action......in case of a mathematical pendulum it moves about the pivoted point.................for deep concepts refer RESNICK AND HALLIDAY......pardon me if in any way im wrong.....
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -