Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

pls derive the equation for escape velocity?!!??!!!!?

pls derive the equation for escape velocity?!!??!!!!?

Grade:9

2 Answers

Sudheesh Singanamalla
114 Points
10 years ago

1756_16302_Scan0001.jpg

 

 

668_16302_Scan0002.jpg

I suggest you to save the two images to your computer first as these pictures might be out of readable range in askIITians forum

 

Please approve

vikas askiitian expert
509 Points
10 years ago

this derivation is based on energy conservation ....

 

when satellite is at earth surface then

total energy = PE + KE

PE = -GMm/R     , (KE)i = ?                       (M is mass of earth )

TE = (KE)i - GMm/R           .....1                  (R is radius of earth)

 

when satellite escapes from earths gravitational field then it reaches to infinity ...

total energy finally = TE = KE + PE

PE = GMm/r          ( r is infinity )

PE = 0 , (KE)f = ?

TE = (KE)f  +  0 = (KE)f   .............2

 

since energy is conserved so eq 1 equals eq 2

-GMm/R + (KE)i = (KE)f

   (KE)i  = GMm/R +  (KE)f        .................3

from this eq we can see that if (KE)f is 0 then (KE) intial is minimum 

value of energy should be given to satellite so that it escapes out...

now , (KE)i = mv2/2 ,  (KE)f = 0 , putting these values in eq 3 we get

v = (2GM/R)1/2

this is the required result...

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free