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sir its a erodov problem
dear raj , here is the sol of ur question ... let initial position of A & B are P , Q .... after time t when they meet then let this point be O ... now joint PQO , this will be a right angled triangle with PO as hypotenuse ... accleration of A & B are alfa & beta .... displacement of B = (beta)t2/2 = QO ...............1 ( by using s = ut + at2/2 ) displacement of A after time t = (alfa)t2/2 = PO ..............2 PQ = L (given) now using pythogorus theorem PO2 = PQ2 + QO2 substituting these values from eq 1, 2 ,3 ((alfa)t2/2)2 = ((beta)t2/2)2 + L2 t = {4L2/[(alfa)2 - (beta)2]} approve if u like my ans
dear raj , here is the sol of ur question ...
let initial position of A & B are P , Q ....
after time t when they meet then let this point be O ...
now joint PQO , this will be a right angled triangle with PO as hypotenuse ...
accleration of A & B are alfa & beta ....
displacement of B = (beta)t2/2 = QO ...............1 ( by using s = ut + at2/2 )
displacement of A after time t = (alfa)t2/2 = PO ..............2
PQ = L (given)
now using pythogorus theorem
PO2 = PQ2 + QO2
substituting these values from eq 1, 2 ,3
((alfa)t2/2)2 = ((beta)t2/2)2 + L2
t = {4L2/[(alfa)2 - (beta)2]}
approve if u like my ans
let initial position of A & B are P , Q ....after time t when they meet then let this point be O ... now joint PQO , this will be a right angled triangle with PO as hypotenuse ... velocities of A,B are u & v .... after time t , displacement of A = ut = PO (speed = distance/time) displacement of B = vt = QO PQ = L now applying pythogorus theorem PQ2 + QO2 = PO2 t =[L2/u2-v2]1/2 this is the required time
let initial position of A & B are P , Q ....after time t when they meet then let this point be O ...
velocities of A,B are u & v ....
after time t ,
displacement of A = ut = PO (speed = distance/time)
displacement of B = vt = QO
PQ = L
now applying pythogorus theorem
PQ2 + QO2 = PO2
t =[L2/u2-v2]1/2
this is the required time
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