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# sir its a erodov problem ## 3 Answers

10 years ago

dear raj , here is the sol of ur question ...

let initial  position of A & B are P , Q ....

after time t when they meet then let this point be O ...

now joint PQO , this will be a right angled triangle with PO as hypotenuse ...

accleration of A & B are alfa & beta ....

displacement of B  = (beta)t2/2  = QO           ...............1               ( by using s = ut + at2/2 )

displacement of A after time t = (alfa)t2/2 = PO             ..............2

PQ = L               (given)

now using pythogorus theorem

PO2 = PQ2 + QO2

substituting these values from eq 1, 2  ,3

((alfa)t2/2)2 = ((beta)t2/2)2 + L2

t = {4L2/[(alfa)2 - (beta)2]}

approve if u like my ans

10 years ago

let initial  position of A & B are P , Q ....

after time t when they meet then let this point be O ...

now joint PQO , this will be a right angled triangle with PO as hypotenuse ...

velocities of A,B are u & v ....

after time t ,

displacement of A = ut  =  PO                             (speed = distance/time)

displacement of B = vt  =  QO

PQ = L

now  applying pythogorus theorem

PQ2 + QO2 = PO2

t =[L2/u2-v2]1/2

this is the required time

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