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```
sir its a erodov problem

```
9 years ago

509 Points
```							dear raj , here is the sol of ur question ...
let initial  position of A & B are P , Q ....

after time t when they meet then let this point be O ...
now joint PQO , this will be a right angled triangle with PO as hypotenuse ...

accleration of A & B are alfa & beta ....
displacement of B  = (beta)t2/2  = QO           ...............1               ( by using s = ut + at2/2 )
displacement of A after time t = (alfa)t2/2 = PO             ..............2
PQ = L               (given)

now using pythogorus theorem
PO2 = PQ2 + QO2
substituting these values from eq 1, 2  ,3
((alfa)t2/2)2 = ((beta)t2/2)2 + L2
t = {4L2/[(alfa)2 - (beta)2]}

approve if u like my ans

```
9 years ago
509 Points
```							let initial  position of A & B are P , Q ....after time t when they meet then let this point be O ...
now joint PQO , this will be a right angled triangle with PO as hypotenuse ...
velocities of A,B are u & v ....
after time t ,
displacement of A = ut  =  PO                             (speed = distance/time)
displacement of B = vt  =  QO
PQ = L

now  applying pythogorus theorem

PQ2 + QO2 = PO2
t =[L2/u2-v2]1/2
this is the required time

```
9 years ago
Sudheesh Singanamalla
114 Points
```							Specify page numbers and question numbers , i can't see the full question !
```
9 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions