sir its a erodov problem

							
dear raj , here is the sol of ur question ...
let initial  position of A & B are P , Q ....
 
after time t when they meet then let this point be O ...
now joint PQO , this will be a right angled triangle with PO as hypotenuse ...
 
accleration of A & B are alfa & beta ....
displacement of B  = (beta)t2/2  = QO           ...............1               ( by using s = ut + at2/2 )
displacement of A after time t = (alfa)t2/2 = PO             ..............2   
PQ = L               (given)
 
now using pythogorus theorem
PO2 = PQ2 + QO2
substituting these values from eq 1, 2  ,3
 ((alfa)t2/2)2 = ((beta)t2/2)2 + L2 
 t = {4L2/[(alfa)2 - (beta)2]}
 
approve if u like my ans
 
 
						

							
let initial  position of A & B are P , Q ....


after time t when they meet then let this point be O ...
now joint PQO , this will be a right angled triangle with PO as hypotenuse ...
velocities of A,B are u & v ....
after time t ,
 displacement of A = ut  =  PO                             (speed = distance/time)
 displacement of B = vt  =  QO
 PQ = L
 
now  applying pythogorus theorem
 
PQ2 + QO2 = PO2
 t =[L2/u2-v2]1/2
this is the required time
 
						

							
Specify page numbers and question numbers , i can't see the full question !