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sir its a erodov problem

sir its a erodov problem


1923_22108_untitled.GIF

Grade:11

3 Answers

vikas askiitian expert
509 Points
10 years ago

dear raj , here is the sol of ur question ...

let initial  position of A & B are P , Q ....

 

after time t when they meet then let this point be O ...

now joint PQO , this will be a right angled triangle with PO as hypotenuse ...

 

accleration of A & B are alfa & beta ....

displacement of B  = (beta)t2/2  = QO           ...............1               ( by using s = ut + at2/2 )

displacement of A after time t = (alfa)t2/2 = PO             ..............2   

PQ = L               (given)

 

now using pythogorus theorem

PO2 = PQ2 + QO2

substituting these values from eq 1, 2  ,3

 ((alfa)t2/2)2 = ((beta)t2/2)2 + L2 

 t = {4L2/[(alfa)2 - (beta)2]}

 

approve if u like my ans

 

 

vikas askiitian expert
509 Points
10 years ago

let initial  position of A & B are P , Q ....


after time t when they meet then let this point be O ...

now joint PQO , this will be a right angled triangle with PO as hypotenuse ...

velocities of A,B are u & v ....

after time t ,

 displacement of A = ut  =  PO                             (speed = distance/time)

 displacement of B = vt  =  QO

 PQ = L

 

now  applying pythogorus theorem

 

PQ2 + QO2 = PO2

 t =[L2/u2-v2]1/2

this is the required time

 

Sudheesh Singanamalla
114 Points
10 years ago

Specify page numbers and question numbers , i can't see the full question !

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