MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Himanshu Dogra Grade: 11
        

Please solve the questions given in the photograph from FIITJEE AITS.


1392_28768_25022011015.jpg

7 years ago

Answers : (4)

vikas askiitian expert
510 Points
										

just after first collision let velociy of bob is v then

 

applying momentam conservation

 

initial momantam of system(Pi) = (m/2) (u)

 u = (2gL)1/2 so Pi = m(2gL)1/2/2

final momemtam (Pf) = mv

 mv = m(2gL)1/2 /2                          (from momentam conservation)

   v = (gL/2)1/2             ................1

KE of bob is mv2/2

KE = mgL/4      ...............2

when bob is at max height then its KE is converted into PE

 mgL/4 = mgHmax

   L/4 = Hmax     

from floor height of bob is L+Hmax = L/4+L = 5L/4                                  (Q15 => option c)

7 years ago
vikas askiitian expert
510 Points
										

let tension in string just after collision is T then

 

T - mg = mv2/r (centripital force)                                         { tension is in upward direction , weight is in downward direction }

 

T = mg + mv2/L

 

v = (gL/2)1/2  so

 

T = 3mg/2               (ans14 =>c )

7 years ago
vikas askiitian expert
510 Points
										

just after second collision , let velocity of bob is v1 & tension in string is T ...

 

after collision this system becomes conical pendulam so verticle component of tension is balanced by weight &

centripital force is provided by horizontal component of tension ...

 

let string makes an angle of @ with verticle then

 

Tcos@ = weight = 2mg       ............1      (weight of bob + particle)

 

Tsin@ = 2mv12 /r              .............2        (r is radius of its path)

r = Lsin@         .........3

from 1,2 & 3

 

v12 = {gLsin@tan@}                  ..................4

 

time period of this system = T = 2pir/v1

                                           = 2pi(Lsin@)/{gLsin@tan@}1/2           ........................5

now , @ can be calculated by using trignometry ... height of this cone = L - L/4 = 3L/4

                                                                      slant height = L

              cos@ = 3/4

so , time perion will be T = 2pi(3L/4g)1/2

7 years ago
vikas askiitian expert
510 Points
										

approve if u like my ans

7 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete Physics Course - Class 12
  • OFFERED PRICE: Rs. 2,756
  • View Details
  • Complete Physics Course - Class 11
  • OFFERED PRICE: Rs. 2,968
  • View Details

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details