 ×     #### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
charges q,q,-2q are placed at the corners of equilateral triangle of side l. what is the net dipole moment? Ans root3 ql. pl explain

```
9 years ago

```							let A,B,C are three vertices ...
charge at A,B is q but at C charge is -2q ...
A(q) ...................B(q)

C(-2q)

charge of C can be written as -q + -q
q charge of A & -q charge of C becomes 1 dipole ...
q charge of B & another -q charge of C makes another dipole ..
direction of dipole moments of  both is rowards C .....
angle bw them will be 60o ...
now resultant = root(p2+p2+2p2cos60o) = root3 (P)
now , P = qL so resultant = root3(qL)
```
9 years ago
```							the answer of the question :the resultant dipole moment of 3 charges placed at the vertices of the triangle is root3qL or -root3 qL
```
8 years ago
```							Explanation given by vikas is correct.Except that “Direction of dipole is from negative to positive.” then only its answer will “root(3)ql”.Otherwise if “direction of dipole moments of  both is towards C …..” it will be in negative j-direction,since it is a vector quantity.Therefore answer will become “-root3(ql)”Y/\|   A(Q)-------------------B(Q)||||             C(-2Q)||----------------------------------->X
```
4 years ago
```							Dipole is only an applicable condition when and only when the charges are also equal in magnitude rather than only being opposite.So, 1st we break -2q charge at C as -q +(-q).Now there are 2 -q charges at C i.e. 1 to complete dipole with A and another with B.Now,Dipole due AC=dipole due BC = q.aSo net dipole = vector sum dipole due AC and due BC where angle b\w the 2 vectors =60°So net dipole=√(qa)²+(qa)²+2qacos60°                        =√3qa
```
3 years ago Yash Chourasiya
246 Points
```							Dear StudentConsider an equilateral triangle of side l. Point A and B have charges +q where A has -2q charge. The system as two dipoles with P1 and P2 along BA and CA respectively. Hence, the magnitude of P1 and P2 are equal to (ql) and the angle between them is 60°. Therefore, the resultant of two is the net dipole moment. Now resultant = √(p2+p2+2p2cos60o) = (P)√3now , P = qLso resultant = qL√3I hope this answer will help you.Thanks & RegardsYash Chourasiya
```
4 months ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Mechanics

View all Questions »  ### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution  ### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions