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charges q,q,-2q are placed at the corners of equilateral triangle of side l. what is the net dipole moment?


Ans root3 ql.


pl explain

8 years ago

Answers : (4)

vikas askiitian expert
509 Points
							

let A,B,C are three vertices ...

charge at A,B is q but at C charge is -2q ...

A(q) ...................B(q)

 

 

           C(-2q)

 

charge of C can be written as -q + -q

q charge of A & -q charge of C becomes 1 dipole ...

q charge of B & another -q charge of C makes another dipole ..

direction of dipole moments of  both is rowards C .....

angle bw them will be 60o ...

now resultant = root(p2+p2+2p2cos60o) = root3 (P)

now , P = qL so resultant = root3(qL)

8 years ago
anu gupta
20 Points
							

the answer of the question :the resultant dipole moment of 3 charges placed at the vertices of the triangle is root3qL or -root3 qL

7 years ago
Arpit
11 Points
							
Explanation given by vikas is correct.
Except that “Direction of dipole is from negative to positive.” then only its answer will “root(3)ql”.
Otherwise if “direction of dipole moments of  both is towards C …..” it will be in negative j-direction,since it is a vector quantity.
Therefore answer will become “-root3(ql)”
Y
/\
|   A(Q)-------------------B(Q)
|
|
|
|             C(-2Q)
|
|----------------------------------->X
3 years ago
Pran
11 Points
							Dipole is only an applicable condition when and only when the charges are also equal in magnitude rather than only being opposite.So, 1st we break -2q charge at C as -q +(-q).Now there are 2 -q charges at C i.e. 1 to complete dipole with A and another with B.Now,Dipole due AC=dipole due BC = q.aSo net dipole = vector sum dipole due AC and due BC where angle b\w the 2 vectors =60°So net dipole=√(qa)²+(qa)²+2qacos60°                        =√3qa
						
2 years ago
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