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A point moves rectilinearly with deceleration whose modulus depends on the velocity 'v' of the particle as a =-k√v where k is a constant, k > 0. At the initial moment the velocity of the particle is 'v 0 '. What distance it will traverse before it stops? What time it will take to cover that distance?

A point moves rectilinearly with deceleration whose modulus depends on the velocity 'v' of the particle as a =-k√v where k is a constant, k > 0. At the initial moment the velocity of the particle is 'v0'. What distance it will traverse before it stops? What  time it will take to cover that distance?

Grade:11

3 Answers

SAGAR SINGH - IIT DELHI
879 Points
12 years ago
Dear student,

a=-k√v

dv/dt=-k√v

dv/√v=-kdt

Now integrate both sides to get velocity as a function of time.

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Askiitians Expert
Sagar Singh
B.Tech, IIT Delhi
sheero
11 Points
6 years ago
but y do we differentiate and itegrate here??
y does the answer not come correctly if i use the equations of motion here
Ankit Jaiswal
165 Points
6 years ago
it is because the retardation is not constant and equations of motion work only for constanr acc.

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