A point moves rectilinearly with deceleration whose modulus depends on the velocity 'v' of the particle as a =-k√v where k is a constant, k 0. At the initial moment the velocity of the particle is 'v 0 '. What distance it will traverse before it stops? What time it will take to cover that distance?

Question

A point moves rectilinearly with deceleration whose modulus depends on the velocity 'v' of the particle as a =-k&radic;v where k is a constant, k > 0. At the initial moment the velocity of the particle is 'v 0 '. What distance it will traverse before it stops? What time it will take to cover that distance?

SAGAR SINGH - IIT DELHI · Answer

Dear student, a=-k&radic;v dv/dt=-k&radic;v dv/&radic;v=-kdt Now integrate both sides to get velocity as a function of time. Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation. All the best. Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian. Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar respectively : Click here to download the toolbar.. Askiitians Expert Sagar Singh B.Tech, IIT Delhi

sheero · Answer

but y do we differentiate and itegrate here?? y does the answer not come correctly if i use the equations of motion here

Ankit Jaiswal · Answer

it is because the retardation is not constant and equations of motion work only for constanr acc.

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