When a body is projected from the ground with an initial velocity'u'with a certain angle with respect to the ground, the magnitude of change in velocity from t=0 to t=0 secs is:

initial velocity = V_i = ucos@ (i) + usin@j

after t time ,

 (vertical comp of velocity ) V_y = (usin@-gt) (j)

horizontal component remains same ..

                   V_x = ucos@

final velocity (V_f) = (ucos@) (i) + (usin@-gt) (j)

change in velocity = V_i- V_f = dV = gt (j)

dV = gt  (change in velocity after time t)

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Approved

Dear student,

Horizontal component of velocity remains same...         

So, V_x = ucos@

final velocity (V_f) = (ucos@) (i) + (usin@-gt) (j)

change in velocity = V_i- V_f = dV = gt (j)

dV = gt  (change in velocity after time t)

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