MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12
        

A particle having velocity V = V0 at t = 0 is decelerated at the rate |a| = β √V , where β is a positive constant. Choose the correct option(s) :-


(a) The particle comes to rest at t = (2 √V0 ) / β


(b) The particle will come to rest at infinty


(c) The distance travelled by the particle is (2 V0 3/2  ) / β


(d) The distance travelled by the particle is (2 V0 3/2  ) /

8 years ago

Answers : (2)

vikas askiitian expert
509 Points
							

a = k(v)1/2

a = dv/dt = -dv/dt in case of retardation

 

-dv/dt = k(v)1/2

 v-1/2dv = -kdt

 [2v1/2] lim from u to v    = -k[t]   lim from 0 to t

 2v1/2 - 2u1/2 = -kt

 u = vo (given) so

 2v1/2 - 2vo1/2 = -kt       ..............1

particle comes to rest when final velocity becomes 0 ,

from eq 1 , put v = 0

    t = 2vo1/2/k                        (option a)

now use v =  dx/dt

 find a relation in bw x & time ,then put t = 2vo1/2 /k u will get the result ...

8 years ago
Aarthi Sundaram
10 Points
							

you have initial velocity u= v0

final velocity, v=0

a= beta/rootV

use v=u+at

you'll get option (a) on isolating t.

simple!!!

8 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details