a balloon ries from rest on the ground with constant accleration g/8 . a stone is dropped ffom a balloon when the ballioon has risen to a height of H m . the time taken by the stone to reach the ground is

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AskiitianExpert Shine · Answer

Hi Applying v 2 -u 2 = 2as ,, gives v2=2*g/8*H , for upward motion of balloon. therefore velocity of stoned while dropped is v= (gh) 0.5 /2 Let the time taken by stone to reach ground is T. apply eq, s=ut + 1/2 a t 2 whr s=H , u=-v , t=T , a=g solve the quadratic equation to get the roots and take the positive root, hence answer is 2(h/g) 0.5 .

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a balloon ries from rest on the ground with constant accleration g/8 . a stone is dropped ffom a balloon when the ballioon has risen to a height of H m . the time taken by the stone to reach the ground is

a balloon ries from rest on the ground with constant accleration g/8 . a stone is dropped ffom a balloon when the ballioon has risen to a height of H m . the time taken by the stone to reach the ground is

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