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TWO BOYS ARE RIDING ON A MERRY GO ROUND WHICH ARE TURNING AT A CONSTANT RATE.BOY 'A' IS AT OUTER RIM.AND BOY 'B' IS CLOSER TO CENTER OF ROTATION.WHO HAS TO HOLD ON TIGHTER?PLZZZ EXPLAIN WITH REASON.(ASSUME THEIR MASSES TO BE SAME).............??????????????

TWO BOYS ARE RIDING ON A MERRY GO ROUND WHICH ARE TURNING AT A CONSTANT RATE.BOY 'A' IS AT OUTER RIM.AND


BOY 'B' IS CLOSER TO CENTER OF ROTATION.WHO HAS TO HOLD ON TIGHTER?PLZZZ EXPLAIN WITH REASON.(ASSUME THEIR


MASSES TO BE SAME).............??????????????

Grade:Upto college level

4 Answers

Shivam Bhagat
22 Points
13 years ago
boy B needs hold more tightly because 1. boy B has to face more centrifugal force as mv2/r=F 2. Boy B has less moment of inertia(mr2)
Ritvik Gautam
85 Points
13 years ago

Boy A has to hold tightly.

 

Reason:

We know,

Torque = RxF

Hence, we can say, that the person who is at a greater distance from the axis of rotation (center of merry-go-round) experiences a greater torque. Since, he faces more torque, hence boy A needs to apply greater force to balance that torque. Therefore, Boy A needs to hold tighter.

 

 

Please Approve!!

 

Shivam Bhagat
22 Points
13 years ago
torque = F*r A F=mv2/r T=mv2/r *r=mv2 B F=mv2/R T=mv2/R *R=mv2 (mv2/r is centrifugal force) So, A and B experience the same torque B experiences greater force as mv2/r=F So r of B is smaller than A so, force will be greater.........
Shivam Bhagat
22 Points
13 years ago
pls cancel all the ans above , the correct ans is- Boy A because it has to face the centrifugal force mv2/R = m(wr)2/r=mw2r. w is equel here so the one with greater radius will face more force , hencce boy A has to hold more tightly. THIS IS CORRECT!!!!! Sorry for wrong ans above.

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