TWO BOYS ARE RIDING ON A MERRY GO ROUND WHICH ARE TURNING AT A CONSTANT RATE.BOY 'A' IS AT OUTER RIM.AND BOY 'B' IS CLOSER TO CENTER OF ROTATION.WHO HAS TO HOLD ON TIGHTER?PLZZZ EXPLAIN WITH REASON.(ASSUME THEIR MASSES TO BE SAME).............??????????????

iit jee Grade: Upto college level

        TWO BOYS ARE RIDING ON A MERRY GO ROUND WHICH ARE TURNING AT A CONSTANT RATE.BOY 'A' IS AT OUTER RIM.AND

BOY 'B' IS CLOSER TO CENTER OF ROTATION.WHO HAS TO HOLD ON TIGHTER?PLZZZ EXPLAIN WITH REASON.(ASSUME THEIR

MASSES TO BE SAME).............??????????????

7 years ago

Answers : (4)

Shivam Bhagat

22 Points

										boy B needs hold more tightly because        1. boy B has to face more centrifugal 

force as mv2/r=F 

2. Boy B has less moment of inertia(mr2)

7 years ago

Disapproved

Ritvik Gautam

85 Points

Boy A has to hold tightly.

Reason:

We know,

Torque = RxF

Hence, we can say, that the person who is at a greater distance from the axis of rotation (center of merry-go-round) experiences a greater torque. Since, he faces more torque, hence boy A needs to apply greater force to balance that torque. Therefore, Boy A needs to hold tighter.

Please Approve!!

7 years ago

Approved

Shivam Bhagat

22 Points

										torque = F*r 
A    F=mv2/r   T=mv2/r *r=mv2
B    F=mv2/R  T=mv2/R *R=mv2
(mv2/r is centrifugal force)
So, A and B experience the same torque 
B experiences greater force as mv2/r=F
So r of B  is smaller than A so, force will be greater.........

7 years ago

Disapproved

Shivam Bhagat

22 Points

										pls cancel all the ans above , the correct ans is-
Boy A because it has to face the centrifugal force mv2/R = m(wr)2/r=mw2r. w is equel here so the one with greater radius will face more force , hencce boy A has to hold more tightly.
THIS IS CORRECT!!!!!

Sorry for wrong ans above.

7 years ago

Disapproved

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