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A bead can slide on a smooth straight wire and a particle of mass m attached to the bead by a light string of length L . The particle is held in contact with the string taut and is then let fall. If the bead has mass 2m then when the string makes an angle θ with the wire, the bead will have slipped a distance______???

A bead can slide on a smooth straight wire and a particle of mass m attached to the bead by a light string of length L . The particle is held in contact with the string taut and is then let fall. If the bead has mass 2m then when the string makes an angle θ with the wire, the bead will have slipped a distance______???

Grade:12

3 Answers

vikas askiitian expert
509 Points
10 years ago

ur question is not clear ....

pls post the diagram then it will be easy to solve ....

Raunaq Mehta
39 Points
5 years ago
since there is no force in the x direction conserve momentum2m(0)+m(l)=2m(x )+m(lcosq+x)solving you get c as answer.
Shubham Gupta
13 Points
2 years ago
As no force acts in the horizontal direction, center of mass of the bead and the particle should remain at the same x-coordinate. 
Initial x-coordinate of the center of mass from the original position of the bead 
= (2m * 0 + m * L) / 3 = L/3 
Final position of the center of mass if the bead has moved by a distance x, 
= [2mx + m(x + Lcosa)] / 3m 
= (3x + Lcosa) / 3 
Equatting COM in both the cases, 
3x + Lcosa = L 
=> x = L(1 - cosa) / 3

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