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Grade: 12
        

A bead can slide on a smooth straight wire and a particle of mass m attached to the bead by a light string of length L . The particle is held in contact with the string taut and is then let fall. If the bead has mass 2m then when the string makes an angle θ with the wire, the bead will have slipped a distance______???

8 years ago

Answers : (3)

vikas askiitian expert
509 Points
							

ur question is not clear ....

pls post the diagram then it will be easy to solve ....

8 years ago
Raunaq Mehta
39 Points
							since there is no force in the x direction conserve momentum2m(0)+m(l)=2m(x )+m(lcosq+x)solving you get c as answer.
						
2 years ago
Shubham Gupta
13 Points
							
As no force acts in the horizontal direction, center of mass of the bead and the particle should remain at the same x-coordinate. 
Initial x-coordinate of the center of mass from the original position of the bead 
= (2m * 0 + m * L) / 3 = L/3 
Final position of the center of mass if the bead has moved by a distance x, 
= [2mx + m(x + Lcosa)] / 3m 
= (3x + Lcosa) / 3 
Equatting COM in both the cases, 
3x + Lcosa = L 
=> x = L(1 - cosa) / 3
3 months ago
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