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Grade: 12

                        

A bead can slide on a smooth straight wire and a particle of mass m attached to the bead by a light string of length L . The particle is held in contact with the string taut and is then let fall. If the bead has mass 2m then when the string makes an angle θ with the wire, the bead will have slipped a distance______???

A bead can slide on a smooth straight wire and a particle of mass m attached to the bead by a light string of length L . The particle is held in contact with the string taut and is then let fall. If the bead has mass 2m then when the string makes an angle θ with the wire, the bead will have slipped a distance______???

10 years ago

Answers : (3)

vikas askiitian expert
509 Points
							

ur question is not clear ....

pls post the diagram then it will be easy to solve ....

10 years ago
Raunaq Mehta
39 Points
							since there is no force in the x direction conserve momentum2m(0)+m(l)=2m(x )+m(lcosq+x)solving you get c as answer.
						
4 years ago
Shubham Gupta
13 Points
							
As no force acts in the horizontal direction, center of mass of the bead and the particle should remain at the same x-coordinate. 
Initial x-coordinate of the center of mass from the original position of the bead 
= (2m * 0 + m * L) / 3 = L/3 
Final position of the center of mass if the bead has moved by a distance x, 
= [2mx + m(x + Lcosa)] / 3m 
= (3x + Lcosa) / 3 
Equatting COM in both the cases, 
3x + Lcosa = L 
=> x = L(1 - cosa) / 3
one year ago
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