Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
Suppose the 1 kg standard body accelerates at 4.00 m/s2at 160(degree) from the positive direction of an x axis due to two forces; one is F1 - (2.50N)i + (4.60N)i What is the otherforce (a) in unit-vector notation and as (b) a magnitude and(c) an angle?
accleration = 4
it makes 160o with +ve x axis so 20o from -ve x axis ...
now resolve accleration into two rectangular components ,
a = 4cos20o (-i) + 4sin20o (j)
net force = ma = 4cos20(-i) + 4sin20(j)
(sin20o similar to sin18o = 0.3 &
cos20o is similar to cos18o = 0.67 )
Fnet = -2.7(i) + 1.2 (j) ...........1
force on particle (Fnet) = F1 + F2
F1 = 2.5(i) + 4.6 (j) so
F2 = -5.2(i) - 3.4 (j) ............2 ans a)
magnitude = (sum of squares of cofficient of x comp & y comp)1/2 = 6.2 (ansc)
unit vector = vector/magnitude
unit vector = -(5.2i + 3.4j)/6.2 = -0.83(i) - 0.55(j) (ans b)
approve if u like my ans
reso;ve the forces into components and separately apply the newton's laws of motion...
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !