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Water stands at a depth of 15 m behind a reservoir dam. A horizontal pipe 4 cm in diameter passes through the dam 6 m below the surface of water as shown. There is plug which secures the pipe opening. Then the friction between the plug and pipe wall is:

```
9 years ago

```							pressure=dgh, d=1000kg/m^3, h=6m, g=9.8m/s^2, area=pi*r2,r=2cm,friction force=pressure*area
```
9 years ago
```							Friction=force applied So, force applied= area×pressure R= d\2= 0.04/2=0.02mArea= pie× R*2=3.14×0.02×0.02=0.001256m*2And pressure=P2- P1=P0+ rho×g×h - P0= rho× g× h= 1000×10×6=60000Therefore, force applied= friction = area× pressure                                           =0.001256×60000                                            =75.36N
```
6 months ago
```							Dear student Above ans are incorrect P = rho * g*h = 58800N/m^2Splug = pi*R^2 Magnitude of the frictional force b/n plug and pipe wallF = S* P = 295.41N V = sqrt(2*g*h)=7.67 m/s
```
6 months ago
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