Join now for JEE/NEET and also prepare for Boards Join now for JEE/NEET and also prepare for Boards. Register Now
Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
A block of mass 'm' sides on a frictionless table. it is constrained to move inside a ring of radius 'R' which is fixed to the table. At t=0, the block is moving along the inside of the ring with velocity 'Vo'. The coefficient of friction between the block and the ring is 'u'.Find the speed and position of the block as the function of 't'. A block of mass 'm' sides on a frictionless table. it is constrained to move inside a ring of radius 'R' which is fixed to the table. At t=0, the block is moving along the inside of the ring with velocity 'Vo'. The coefficient of friction between the block and the ring is 'u'.Find the speed and position of the block as the function of 't'.
A block of mass 'm' sides on a frictionless table. it is constrained to move inside a ring of radius 'R' which is fixed to the table. At t=0, the block is moving along the inside of the ring with velocity 'Vo'. The coefficient of friction between the block and the ring is 'u'.Find the speed and position of the block as the function of 't'.
friction acting on the block at any time is f ... f = k(normal reaction) (k is cofficient of friction) normal reaction (N)= mv2/R (mass is in contact with ring) f = ma = uN a = -kv2/R (-ve sign coz , friction produces retardation) now , a = dv/dt dv/dt = -k v2/R dv/v2 = -kdt/R integrating both sides (-1/v) = -kt/R + C ...........1 ( C is constant of integration) now at t=0 , v = vo (given) so C = -1/vo , after plugging value eq 1 becomes -1/v = -kt/R - 1/vo v = [Rvo/(R+vokt)]
friction acting on the block at any time is f ...
f = k(normal reaction) (k is cofficient of friction)
normal reaction (N)= mv2/R (mass is in contact with ring)
f = ma = uN
a = -kv2/R (-ve sign coz , friction produces retardation)
now , a = dv/dt
dv/dt = -k v2/R
dv/v2 = -kdt/R
integrating both sides
(-1/v) = -kt/R + C ...........1 ( C is constant of integration)
now at t=0 , v = vo (given) so
C = -1/vo , after plugging value eq 1 becomes
-1/v = -kt/R - 1/vo
v = [Rvo/(R+vokt)]
thnx...
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -