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Mechanics

Four particles of equal masses M move along a circle of radius R under the action of their mutual gravitational attraction. Find the speed of each particle.

Profile image of kanchana Rao
15 Years agoGrade
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2 Answers

Profile image of vikas askiitian expert
15 Years ago

net force on any of particle due to remaining three = GM2 (81/2+1)/4R2

centripital force is provided by mutual gravitational force

GM2 (81/2+1)/4R2 = MV2/R

  V = [GM(81/2+1)/4R]

Profile image of sai raghava rajeev penagamuri
15 Years ago

SQUARE ROOT OF GM/R(2(1.414)+1)/4